某公司需招聘一名员工，对应聘者*、乙、*从笔试、面试、体能三个方面进行量化考核，*、乙、*各项得分如下表：笔试...

问题详情：

某公司需招聘一名员工，对应聘者*、乙、*从笔试、面试、体能三个方面进行量化考核，*、乙、*各项得分如下表：

    (1)根据三项得分的平均分，从高到低确定三名应聘者的排名顺序．

(2)该公司规定：笔试，面试、体能得分分别不得低于80分，80分，70分，并按60%，30%，10%的比例计入总分，根据规定，请你说明谁将被录用．

【回答】

 解：(1) =（83+79+90）÷3=84，

=（85+80+75）÷3=80，

=（80+90+73）÷3=81．············································································ 3分

从高到低确定三名应聘者的排名顺序为：*，*，乙；··································· 4分

(2)∵该公司规定：笔试，面试、体能得分分别不得低于80分，80分，70分，

∴*淘汰，···································································································· 5分

乙成绩=85×60%+80×30%+75×10%=82.5，······················································· 7分

*成绩=80×60%+90×30%+73×10%=82.3，····················································· 9分

∴乙将被录取．  ························································································· 10分

知识点：数据的波动程度

题型：解答题